A. MAX
B. MIN
C. SUM
D. COUNT
E. TOTAL
F. LARGEST
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A. The main query executes with the first value returned by the subquery.
B. The main query executes with the last value returned by the subquery.
C. The main query executes with all the values returned by the subquery.
D. The main query fails because the multiple-row subquery cannot be used with the comparison operator.
E. You cannot define a multiple-row subquery in the WHERE clause of a SQL query.
A.Constraints provide data independence.
B.Constraints make complex queries easy.
C.Constraints enforce rules at the view level.
D.Constraints enforce rules at the table level.
E.Constraints prevent the deletion of a table if there are dependencies.
F.Constraints prevent the deletion of an index if there are dependencies.
A.TRIM
B.REPLACE
C.TRUNC
D.TO_DATE
E.MOD
F.CASE
Evaluate this SQL statement:
SELECT e.EMPLOYEE_ID,e.LAST_NAME,e.DEPARTMENT_ID, d.DEPARTMENT_NAME FROM EMP e, DEPARTMENT d
WHERE e.DEPARTMENT_ID = d.DEPARTMENT_ID;
In the statement, which capabilities of a SELECT statement are performed?（）
A. Selection, projection, join
B. Difference, projection, join
C. Selection, intersection, join
D. Intersection, projection, join
E. Difference, projection, product
A. Use the DESCRIBE command in the EMP_DEPT VU view.
B. Use the DEFINE VIEW command on the EMP_DEPT VU view.
C. Use the DESCRIBE VIEW command on the EMP_DEPT VU view.
D. Query the USER_VIEWS data dictionary view to search for the EMP_DEPT_VU view.
E. Query the USER_SOURCE data dictionary view to search for the EMP_DEPT_VU view.
F. Query the USER_OBJECTS data dictionary view to search for the EMP_DEPT_VU view.
A. SELECT last_name FROM EMP WHERE last_ name LIKE '_A%';
B. SELECT last_name FROM EMP WHERE last name ='*A%'
C. SELECT last_name FROM EMP WHERE last name ='_A%';
D. SELECT last_name FROM EMP WHERE last name LIKE '*A%'
The ORDERS table has these columns:
The ORDERS table tracks the Order number, the order total, and the customer to whom the Order belongs. Which two statements retrieve orders with an inclusive total that ranges between 100.00 and 2000.00 dollars?（）
A. SELECT customer_id, order_id, order_total FROM orders RANGE ON order_total (100 AND 2000) INCLUSIVE;
B. SELECT customer_id, order_id, order_total FROM orders HAVING order_total BETWEEN 100 and 2000;
C. SELECT customer_id, order_id, order_total FROM orders WHERE order_total BETWEEN 100 and 2000;
D. SELECT customer_id, order_id, order_total FROM orders WHERE order_total >= 100 and <= 2000;
E. SELECT customer_id, order_id, order_total FROM orders WHERE order_total >= 100 and order_total <= 2000;
Examine the data from the ORDERS and CUSTOMERS tables.
ORDERS
ORD_ID ORD_DATE CUST_ID
12-JAN-
100 15 10000
09-MAR-
101 40 8000
09-MAR-
102 35 12500
15-MAR-
103 15 12000
25-JUN-
104 15 6000
18-JUL-
105 20 5000
106 18-JUL- 35 7000
21-JUL-
107 20 6500
04-AUG-
109 10 8000
CUSTOMERS
CUST_ID CUST_NAME CITY
10 Smith Los Angeles
15 Bob San Francisco
20 Martin Chicago
25 Mary New York
30 Rina Chicago
35 Smith New York
40 Lind New York
Evaluate the SQL statement:
SELECT *
FROM orders
WHERE cust_id = (SELECT cust_id
FROM customers
WHERE cust_name = 'Smith');
What is the result when the query is executed?（）
A. ORD_ID ORD_DATE CUST_ID ORD_TOTAL 09-MAR- 102 35 12500 18-JUL- 106 35 7000 04-AUG- 108 10 8000
B. ORD_ID ORD_DATE CUST_ID ORD_TOTAL 09-MAR- 102 35 12500 18-JUL- 106 35 7000
C. ORD_ID ORD_DATE CUST_ID ORD_TOTAL 04-AUG- 108 10 8000
D. The query fails because the subquery returns more than one row.
E. The query fails because the outer query and the inner query are using different tables.
Examine the structure of the EMPLOYEES, DEPARTMENTS, and TAX tables.
EMPLOYEES
NOT NULL, Primary
EMPLOYEE_ID NUMBER
Key
VARCHAR2
EMP_NAME
(30)
VARCHAR2
JOB_ID
(20)
SALARY NUMBER
References
MGR_ID NUMBER
EMPLOYEE_ID
column
DEPARTMENT_ID NUMBER Foreign key to
DEPARTMENT_ID
column of
the DEPARTMENTS
table
DEPARTMENTS
NOT NULL,
DEPARTMENT_ID NUMBER
Primary Key
VARCHAR2
DEPARTMENT_NAME
|30|
References
MGR_ID column
MGR_ID NUMBER
of the
EMPLOYEES table
TAX
MIN_SALARY NUMBER
MAX_SALARY NUMBER
TAX_PERCENT NUMBER
For which situation would you use a nonequijoin query?（）
A. To find the tax percentage for each of the employees.
B. To list the name, job id, and manager name for all the employees.
C. To find the name, salary, and department name of employees who are not working with Smith.
D. To find the number of employees working for the Administrative department and earning less then 4000.
E. To display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned.
最新试题
Which four are types of functions available in SQL? （）
In which two cases would you use an outer join? （）
Which is a valid CREATE TABLE statement? （）
Which statement accomplish this? （）
Examine the structure of the EMPLOYEES table:EMPLOYEE_ID NUMBER NOT NULL, Primary KeyEMP_NAME VARCHAR2(30)JOB_ID NUMBER\SAL NUMBERMGR_ID NUMBER References EMPLOYEE_ID columnDEPARTMENT_ID NUMBER Foreign key to DEPARTMENT_ID column of the DEPARTMENTS table You created a sequence called EMP_ID_SEQ inorderto populate sequential values for the EMPLOYEE_ID column of the EMPLOYEES table. Which two statements regarding the EMP_ID_SEQ sequence are true? （）
User Mary has a view called EMP_DEPT_LOC_VU that was created based on the EMPLOYEES, DEPARTMENTS, and LOCATIONS tables. She has the privilege to create a public synonym, and would like to create a synonym for this view that can be used by all users of the database. Which SQL statement can Mary use to accomplish that task?（）
Which three are true? （）
Which statement correctly describes SQL and /SQL*Plus? （）
Which three statements about subqueries are true? （）
Which two statements about subqueries are true? （）