已知程序段如下执行结果是()
A.无法运算 B.4 C.8 D.0
A.p=&b;scanf("%d",&p); B.scanf("%d",&b);*p=b; C.p=&b;scanf("%d",*p); D.p=&b;*p=a;
A.int*_k B.char*_245 C.int*p D.double*5_is