单项选择题

CaCl2 摩尔电导率与其离子的摩尔电导率的关系是

A．L¥(CaCl2) = lm(Ca2+) + lm(Cl-)
B．L¥(CaCl2) = ½ lm(Ca2+) + lm(Cl-)
C．L¥(CaCl2) = lm(Ca2+) + 2lm(Cl-)
D．L¥(CaCl2) = 2 [lm(Ca2+) + lm(Cl-)]

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