A.172.31.17.4 /30
B.172.31.51.16 /30
C.172.31.64.0 /18
D.172.31.80.0 /22
E.172.31.92.0 /22
F.172.31.192.0 /18
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A.ipv6 address PREFIX_1::1/64
B.ipv6 autoconfig 2001:db8:2222:7272::72/64
C.ipv6 autoconfig
D.ipv6 address 2001:db8:2222:7272::72/64
A.Network A - 172.16.3.48/26
B.Network A - 172.16.3.128/25
C.Network A - 172.16.3.192/26
D.Link A - 172.16.3.0/30
E.Link A - 172.16.3.40/30
F.Link A - 172.16.3.112/30
What can be determined from the line of show ip route output shown in the exhibit?()
A.The next routing update can be expected in 35 seconds.
B.The IP address 10.10.10.6 is configured on S0/1.
C.The IP address 10.10.10.8 is configured on S0/1.
D.This route is using the default administrative distance.
E.The 10.10.10.8 network is two hops away from this router.
A.access-group
B.access-list
C.acl
D.firewall packet-filter xxxx inbound/outbound
A.the IP address of Switch 1
B.the MAC address of Switch 1
C.the IP address of Host C
D.the MAC address of Host C
E.the IP address of the router's E0 interface
F.the MAC address of the router's E0 interface
A.对端的IP地址和对端的x.121地址
B.对端的IP地址和本接口的x.121地址
C.本接口的IP地址和对端的x.121地址
D.本接口的IP地址和本接口的x.121地址
A.Broadcast frames are never sent to swiches.
B.Broadcast addresses use an incorrect format for the switching table.
C.A broadcast address will never be the source address of a frame.
D.Broadcasts only use network layer addressing.
E.A broadcast frame is never forwarded by a switch.
A.show ip interface [interface] access-lists
B.show ip access-lists interface [interface]
C.show ip interface [interface]
D.show ip access-lists [interface]
A.分组层
B.数据链路层
C.物理层
D.传输层
E.网络层
A.buffering
B.cut-through
C.windowing
D.congestion avoidance
E.load balancing
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最新试题
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